3.1110 \(\int \frac{(e x)^{9/2} \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx\)

Optimal. Leaf size=180 \[ -\frac{7 a^{3/2} e^4 \sqrt{e x} \sqrt [4]{\frac{a}{b x^2}+1} (10 b c-11 a d) E\left (\left .\frac{1}{2} \cot ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{20 b^{7/2} \sqrt [4]{a+b x^2}}-\frac{7 a e^3 (e x)^{3/2} (10 b c-11 a d)}{60 b^3 \sqrt [4]{a+b x^2}}+\frac{e (e x)^{7/2} (10 b c-11 a d)}{30 b^2 \sqrt [4]{a+b x^2}}+\frac{d (e x)^{11/2}}{5 b e \sqrt [4]{a+b x^2}} \]

[Out]

(-7*a*(10*b*c - 11*a*d)*e^3*(e*x)^(3/2))/(60*b^3*(a + b*x^2)^(1/4)) + ((10*b*c -
 11*a*d)*e*(e*x)^(7/2))/(30*b^2*(a + b*x^2)^(1/4)) + (d*(e*x)^(11/2))/(5*b*e*(a
+ b*x^2)^(1/4)) - (7*a^(3/2)*(10*b*c - 11*a*d)*e^4*(1 + a/(b*x^2))^(1/4)*Sqrt[e*
x]*EllipticE[ArcCot[(Sqrt[b]*x)/Sqrt[a]]/2, 2])/(20*b^(7/2)*(a + b*x^2)^(1/4))

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Rubi [A]  time = 0.310552, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192 \[ -\frac{7 a^{3/2} e^4 \sqrt{e x} \sqrt [4]{\frac{a}{b x^2}+1} (10 b c-11 a d) E\left (\left .\frac{1}{2} \cot ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )\right |2\right )}{20 b^{7/2} \sqrt [4]{a+b x^2}}-\frac{7 a e^3 (e x)^{3/2} (10 b c-11 a d)}{60 b^3 \sqrt [4]{a+b x^2}}+\frac{e (e x)^{7/2} (10 b c-11 a d)}{30 b^2 \sqrt [4]{a+b x^2}}+\frac{d (e x)^{11/2}}{5 b e \sqrt [4]{a+b x^2}} \]

Antiderivative was successfully verified.

[In]  Int[((e*x)^(9/2)*(c + d*x^2))/(a + b*x^2)^(5/4),x]

[Out]

(-7*a*(10*b*c - 11*a*d)*e^3*(e*x)^(3/2))/(60*b^3*(a + b*x^2)^(1/4)) + ((10*b*c -
 11*a*d)*e*(e*x)^(7/2))/(30*b^2*(a + b*x^2)^(1/4)) + (d*(e*x)^(11/2))/(5*b*e*(a
+ b*x^2)^(1/4)) - (7*a^(3/2)*(10*b*c - 11*a*d)*e^4*(1 + a/(b*x^2))^(1/4)*Sqrt[e*
x]*EllipticE[ArcCot[(Sqrt[b]*x)/Sqrt[a]]/2, 2])/(20*b^(7/2)*(a + b*x^2)^(1/4))

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Rubi in Sympy [F]  time = 0., size = 0, normalized size = 0. \[ \frac{7 a^{2} e^{4} \sqrt{e x} \left (11 a d - 10 b c\right ) \sqrt [4]{\frac{a}{b x^{2}} + 1} \int ^{\frac{1}{x}} \frac{1}{\left (\frac{a x^{2}}{b} + 1\right )^{\frac{5}{4}}}\, dx}{40 b^{4} \sqrt [4]{a + b x^{2}}} + \frac{7 a e^{3} \left (e x\right )^{\frac{3}{2}} \left (11 a d - 10 b c\right )}{60 b^{3} \sqrt [4]{a + b x^{2}}} + \frac{d \left (e x\right )^{\frac{11}{2}}}{5 b e \sqrt [4]{a + b x^{2}}} - \frac{e \left (e x\right )^{\frac{7}{2}} \left (11 a d - 10 b c\right )}{30 b^{2} \sqrt [4]{a + b x^{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((e*x)**(9/2)*(d*x**2+c)/(b*x**2+a)**(5/4),x)

[Out]

7*a**2*e**4*sqrt(e*x)*(11*a*d - 10*b*c)*(a/(b*x**2) + 1)**(1/4)*Integral((a*x**2
/b + 1)**(-5/4), (x, 1/x))/(40*b**4*(a + b*x**2)**(1/4)) + 7*a*e**3*(e*x)**(3/2)
*(11*a*d - 10*b*c)/(60*b**3*(a + b*x**2)**(1/4)) + d*(e*x)**(11/2)/(5*b*e*(a + b
*x**2)**(1/4)) - e*(e*x)**(7/2)*(11*a*d - 10*b*c)/(30*b**2*(a + b*x**2)**(1/4))

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Mathematica [C]  time = 0.165026, size = 111, normalized size = 0.62 \[ \frac{e^3 (e x)^{3/2} \left (-77 a^2 d+7 a \sqrt [4]{\frac{b x^2}{a}+1} (11 a d-10 b c) \, _2F_1\left (\frac{1}{4},\frac{3}{4};\frac{7}{4};-\frac{b x^2}{a}\right )+a b \left (70 c-11 d x^2\right )+2 b^2 x^2 \left (5 c+3 d x^2\right )\right )}{30 b^3 \sqrt [4]{a+b x^2}} \]

Antiderivative was successfully verified.

[In]  Integrate[((e*x)^(9/2)*(c + d*x^2))/(a + b*x^2)^(5/4),x]

[Out]

(e^3*(e*x)^(3/2)*(-77*a^2*d + a*b*(70*c - 11*d*x^2) + 2*b^2*x^2*(5*c + 3*d*x^2)
+ 7*a*(-10*b*c + 11*a*d)*(1 + (b*x^2)/a)^(1/4)*Hypergeometric2F1[1/4, 3/4, 7/4,
-((b*x^2)/a)]))/(30*b^3*(a + b*x^2)^(1/4))

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Maple [F]  time = 0.108, size = 0, normalized size = 0. \[ \int{(d{x}^{2}+c) \left ( ex \right ) ^{{\frac{9}{2}}} \left ( b{x}^{2}+a \right ) ^{-{\frac{5}{4}}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((e*x)^(9/2)*(d*x^2+c)/(b*x^2+a)^(5/4),x)

[Out]

int((e*x)^(9/2)*(d*x^2+c)/(b*x^2+a)^(5/4),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (d x^{2} + c\right )} \left (e x\right )^{\frac{9}{2}}}{{\left (b x^{2} + a\right )}^{\frac{5}{4}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((d*x^2 + c)*(e*x)^(9/2)/(b*x^2 + a)^(5/4),x, algorithm="maxima")

[Out]

integrate((d*x^2 + c)*(e*x)^(9/2)/(b*x^2 + a)^(5/4), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{{\left (d e^{4} x^{6} + c e^{4} x^{4}\right )} \sqrt{e x}}{{\left (b x^{2} + a\right )}^{\frac{5}{4}}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((d*x^2 + c)*(e*x)^(9/2)/(b*x^2 + a)^(5/4),x, algorithm="fricas")

[Out]

integral((d*e^4*x^6 + c*e^4*x^4)*sqrt(e*x)/(b*x^2 + a)^(5/4), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((e*x)**(9/2)*(d*x**2+c)/(b*x**2+a)**(5/4),x)

[Out]

Timed out

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GIAC/XCAS [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (d x^{2} + c\right )} \left (e x\right )^{\frac{9}{2}}}{{\left (b x^{2} + a\right )}^{\frac{5}{4}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((d*x^2 + c)*(e*x)^(9/2)/(b*x^2 + a)^(5/4),x, algorithm="giac")

[Out]

integrate((d*x^2 + c)*(e*x)^(9/2)/(b*x^2 + a)^(5/4), x)